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3x^2-6x-864=0
a = 3; b = -6; c = -864;
Δ = b2-4ac
Δ = -62-4·3·(-864)
Δ = 10404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10404}=102$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-102}{2*3}=\frac{-96}{6} =-16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+102}{2*3}=\frac{108}{6} =18 $
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